Second Equation of Motion


 
 
Concept Explanation
 

Second Equation of Motion

SECOND EQUATION OF MOTION:

large s=ut+frac{1}{2}at^{2}

Displacement = initial velocity large times large frac{1}{2}  large times acceleration large times  large time;interval^{2}

Distance travelled = average velocity large times time = large left ( frac{Initial;velocity+final;velocity}{2} right )times time

    or   large s=frac{u+v}{2}times t

But from eq. (1), v = u + at

        large therefore   large s=frac{u+(u+at)}{2}times t      or     large s=frac{2u+at}{2}times t

    or   large s=ut+frac{1}{2}at^{2}

Sample Questions
(More Questions for each concept available in Login)
Question : 1

A body starts moving with an initial velocity of  4;m;s^-^1 and an acceleration of x;m;s^-^2 If the distance travelled by it is 30 m in 2^n^d s, then the value of x is ______ .

Right Option : D
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Explanation
Question : 2

A driver applies brakes when he sees a child on the railway track, the speed of the train reduces from  54 : km: h^-1: : to : : 18: km: h ^-1: : in: : 5 s. What is the distance travelled by the train during this interval of time ?

Right Option : B
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Explanation
Question : 3

A body is dropped from the top of a tower. If its average velocity , when it reaches the ground ,  is   large 20m/sec and the time taken by it to reach the ground is 2sec  ;  the height of the tower is _______________ m.

Right Option : A
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Explanation
 
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